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Connecting Homomorphism

ConnectingHomomorphism

The homomorphism S which, according to the snake lemma, permits construction of an exact sequence

 

 Ker(alpha)-->Ker(beta)-->Ker(gamma)-->^Scoker(alpha)-->coker(beta)-->coker(gamma)
(1)

 

from the above commutative diagram with exact rows. The homomorphism S is defined by

 

 S(c)=a^'+Im(alpha)
(2)

 

for all c in Ker(gamma), Im denotes the image, and a^' is obtained through the following construction, based on diagram chasing.

 

1. Exploit the surjectivity of g to find b in B such that c=g(b).


2. Since 0=gamma(c)=gamma(g(b))=g^'(beta(b)) because of the commutativity of the right square, beta(b) belongs to Ker(g^'), which is equal to Im(f^') due to the exactness of the lower row at B^'. This allows us to find a^' in A^' such that beta(b)=f^'(a^').

While the elements b and a^' are not uniquely determined, the coset a^'+Im(alpha) is, as can be proven by using more diagram chasing. In particular, if b^_ and a^_^' are other elements fulfilling the requirements of steps (1) and (2), then c=g(b^_) and beta(b^_)=f^'(a^_^'), and

 0=c-c=g(b)-g(b^_)=g(b-b^_),
(3)

hence b-b^_ in Ker(g)=Im(f) because of the exactness of the upper row at B. Let a in A be such that

 b-b^_=f(a).
(4)

Then

 f^'(a^'-a^_^')=f^'(a^')-f^'(a^_^')=beta(b)-beta(b^_)=beta(b-b^_)=beta(f(a))=f^'(alpha(a)),
(5)

because the left square is commutative. Since f^' is injective, it follows that

 a^'-a^_^'=alpha(a) in Im(alpha),
(6)

and so

 a^'+Im(alpha)=a^_^'+Im(alpha).
(7)

SEE ALSO:Cokernel, Commutative Diagram, Diagram Chasing, Exact Sequence, Group Kernel, Snake Lemma

This entry contributed by Margherita Barile


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